An oxide XO\(_2\) has a vapour density of 32. What is the atomic mass of X?
A
32
B
20
C
14
D
12
Verified Correct Answer: A.
Chemical Principles & Mechanism
Relative molecular mass of XO\(_2\) = 2 \times vapour density
Relative molecular mass → (2 x 32) = 64
Atomic mass of X:
X + [16 x 2] = 64
X = 64 - 32
= 32
Source: WAEC / JAMB / NECO Classroom Archive (Record #1579)