The maximum current drawn by the cooker is given by; I = \(\frac{P}{V}\) ∴ I = \(\frac{\text{3000}}{200}\) I = 15A The fuse rating = I \(\times\) 125% (the fuse is rated at 125% of the normal operating current) Hence, the fuse rating = 15A \(\times\) (\(\frac{125}{100}\)) = 18.75amps Therefore, the best fuse is 20A.