The fourth overtone of a closed pipes is 900Hz, its fundamental frequency is
A
50Hz
B
100Hz
C
200Hz
D
400Hz
Verified Correct Answer: B.
Step-by-Step Mathematical Solution
For a closed pipe, only odd harmonics are present. first overtone frequency is 3f\(_o\), 2\(^{nd}\) overtone frequency is 5f\(_o\) etc.
4\(^{th}\) overtone frequency = 9f\(_o\)
900 = 9f\(_o\)
f\(_o\) = \(\frac{900}{9}\) = 100Hz
Source: WAEC / JAMB / NECO Classroom Archive (Record #70425)