When the tension in a sonometer wire is doubled, the ratio of the new frequency to the initial frequency is?
A
\(\frac{1}{\sqrt2}\)
B
\(\frac{1}{2}\)
C
\(\sqrt2\)
D
2
Verified Correct Answer: C.
Physical Principles & Numerical Solution
\(\frac{F_1}{F_2}\) = \(\sqrt{\frac{T_1}{T_2}}\)
\(T_2 = 2T_1\)
\(\frac{F_1}{F_2}\) = \(\sqrt{\frac{T_1}{2T_1}}\)
\(\frac{F_1}{F_2} = \frac{1}{ \sqrt2}\)
F\(_1\) : F\(_2\) = 1 : \(\sqrt{2}\)
F\(_2\) : F\(_1\) = \(\sqrt{2}\) : 1
Source: WAEC / JAMB / NECO Classroom Archive (Record #28340)