A source of sound produces waves in air of wavelength 1.65m. If the speed of sound in air is 330ms\(^{-1}\), the period of vibration in air is?
A
200
B
0.005
C
0.5
D
0.02
Verified Correct Answer: B.
Physical Principles & Numerical Solution
V = \(\frac{\lambda}{T}\)
: v = 330ms\(^{-1}\)
\(\lambda\) = 1.65m
T = ?
330 = 1.65
T = \(\frac{1.65}{330}\) = 0.005s
Source: WAEC / JAMB / NECO Classroom Archive (Record #60734)