The distance between two successive crests of a water wave is 0.25m. If a particle on the surface of the water makes four complete vertical oscillations in one second. Calculate the speed of the wave.
A
4ms\(^{-1}\)
B
3ms\(^{-1}\)
C
2ms\(^{-1}\)
D
1ms\(^{-1}\)
Verified Correct Answer: D.
Physical Principles & Numerical Solution
distance between two successive crests of a water wave = \(\lambda\) = 0.25m
Frequency (f) is defined as the number of cycles or oscillations that occur in one second = four complete vertical oscillations in one second = 4Hz
Speed of wave (v) = f x \(\lambda\) = 0.25 x 4 = 1m/s
Source: WAEC / JAMB / NECO Classroom Archive (Record #70410)