Given that SQ = 10cm and SR = 6cm, the refractive index of the block of glass shown in the above figure is
Attached Figure / Diagram
A
1.67
B
0.60
C
0.30
D
2.33
Verified Correct Answer: A.
Step-by-Step Mathematical Solution
For a ray entering and exiting parallel faces of a glass slab, the refractive index is given by:
n = \(\frac{\text{real depth}}{\text{apparent depth}}\)
Where SR = 6cm is apparent depth, SQ = 10cm real depth.
n = \(\frac{10}{6}\) = 1.6666 ≈ 1.67
Source: WAEC / JAMB / NECO Classroom Archive (Record #74660)