Calculate the critical angle for light traveling from water to air. (Refractive index of water = 1.33)
A
36.9°
B
41.3°
C
48.8°
D
49.2°
E
51.4°
Verified Correct Answer: C.
Physical Principles & Numerical Solution
critical angle formula = \(sin^{-1}\) \(\frac{n_2}{n_1}\)
→ \(sin^{-1}\) \(\frac{1}{1.33}\) = \(sin^{-1}\) 0.7518
= 48.75º
Source: WAEC / JAMB / NECO Classroom Archive (Record #42928)