If the frequency of an emitted x-ray is 1.6 x 10\(^{16}\)Hz, the accelerating potential is?
[e = 1.6 x 10\(^{-19}\)J, h = 6.63 x 10-\(^{34}\)Js]
A
6630.0V
B
663.0V
C
66.3V
D
6.6V
Verified Correct Answer: C.
Physical Principles & Numerical Solution
Given f = 1.6 x10\(^{16}\)\(H_3\), h = 6.63 x 10\(^{-39}\)Js
e = 1.6 x 10\(^{-19}\)C, V = ?
V = \(\frac{w}{e} = \frac{hf}{e}\) = \(\frac{1.6 \times 10^{16} \times 6.63 \times 10^{34}}{1.6 \times 10^{-19}}\)
= 66.3V
Source: WAEC / JAMB / NECO Classroom Archive (Record #60745)