The ground state energy for the hydrogen atom is 5.44 x 10\(^{-19}\)J. If an electron drops from zero energy to the ground state, calculate the frequency of the emitted radiation. [h = 6.6 x 10\(^{-34}\) Js]
A
5.0 x 1016 Hz
B
2.0 x 1016 Hz
C
5.0 x 1015 Hz
D
2.0 x 1015 Hz
E
No correct option
Verified Correct Answer: E.
Physical Principles & Numerical Solution
∆E = hf
f = (∆E)/h = (5.44 x 10-19)/6.6 x 10-34 = 8.24 x 1014
Source: WAEC / JAMB / NECO Classroom Archive (Record #14345)