If the current in the resistor R is 0.05 A, calculate the p.d across the inductor.
Attached Figure / Diagram
A
2.5 V
B
49.0 V
C
25.0 V
D
50.0 V
Verified Correct Answer: A.
Physical Principles & Numerical Solution
I = 0.05 A, p.d across R\(_L\) = V\(_L\) = I R\(_L\) = 0.05 \times 50
V\(_L\) = 2.5 V
Source: WAEC / JAMB / NECO Classroom Archive (Record #76399)