Calculate the inductance L of the COIL in the circuit shown above
Attached Figure / Diagram
A
3.8 H
B
0.4 H
C
0.6 H
D
14.4 H
Verified Correct Answer: C.
Step-by-Step Mathematical Solution
V = I X\(_L\)
X\(_L\) = \(\frac{\text{V }}{\text{I}}\) = \(\frac{240}{2}\) = 120 Ω
But X\(_L\) = 2\(\pi\)fL
120 = 2 x 2\(\pi\) x \(\frac{100}{\pi}\) x L
120 = 2 x 100 x L = 200L
L = \(\frac{120}{200}\) = 0.6H
Source: WAEC / JAMB / NECO Classroom Archive (Record #76389)