The electrical power developed in the resistor above is
Attached Figure / Diagram
A
8 W
B
64 W
C
256 W
D
128 W
Verified Correct Answer: D.
Step-by-Step Mathematical Solution
Power P dissipated in a resistor is given by:
P = \(\frac{V^2}{\text{R}}\)
where V =16 V, and R = 2 Ω
P = \(\frac{(16)^2}{2}\) = \(\frac{256}{2}\) = 128W
Source: WAEC / JAMB / NECO Classroom Archive (Record #78254)