The resistance \(R\) of a wire is related to its resistivity \(\rho\), length \(L\), and cross-sectional area \(A\) by the formula: \(R = \frac{\rho L}{A}\) The conductivity \(\sigma\) is the reciprocal of the resistivity: \(\sigma = \frac{1}{\rho}\) \(\rho = \frac{R A}{L}\) \(\sigma = \frac{L}{R A}\) Substitute the given values (\(L = 5\) m, \(R = 10\) \Omega, \(A = 4.0 \times 10^{-3}\) m²): \(\sigma = \frac{5}{10 \times 4.0 \times 10^{-3}} = \frac{5}{0.04} = 125\) The conductivity of the wire is 125 \Omega\(^{-1}\)m\(^{-1}\) = 1.25 x 10\(^2\) \Omega\(^{-1}\)m\(^{-1}\)