The equivalent capacitance of the capacitors in the circuit above
Attached Figure / Diagram
A
\(\frac{5}{2}\)C
B
4C
C
\(\frac{3}{2}\)C
D
2C
Verified Correct Answer: A.
Physical Principles & Numerical Solution
Capacitance in parallel = one at the top + one under = 2C
The two in the middle are in series = \(\frac{C}{2}\)
The equivalent capacitance of the capacitors in the circuit above = \(\frac{C}{2}\) + 2C = \(\frac{5}{2}\)C
Source: WAEC / JAMB / NECO Classroom Archive (Record #70664)