A cell whose internal resistance is 0.55\(\Omega\) delivers a current of 4 A to an external resistor. The lost voltage of the cell is?
A
4.00 V
B
2.20 V
C
0.15 V
D
8.00 V
Verified Correct Answer: B.
Physical Principles & Numerical Solution
Lost voltage = I x R
= 4 x 0.55
= 2.2V
Source: WAEC / JAMB / NECO Classroom Archive (Record #64923)