The diagram above shows three circuits, the internal resistances of the batteries are negligible. which of the currents is the largest
Attached Figure / Diagram
A
I1
B
I2
C
I3
D
I4
E
I5
Verified Correct Answer: E.
Physical Principles & Numerical Solution
Current = \(\frac{\text{Voltage}}{\text{Resistance}}\)
I\(_1 = \frac{10}{2}\) = 5A
I\(_2 = \frac{10}{1}\) = 10A
I\(_3 = \frac{20}{3}\) = 6.67A
I\(_4 = \frac{20}{2}\) = 10A
I\(_5 = \frac{20}{1}\) = 20A
Source: WAEC / JAMB / NECO Classroom Archive (Record #41641)