The effective capacitance between points X and Y in the diagram above is 1.0\(\mu\) F. What is the value of the capacitance?
Attached Figure / Diagram
A
5.0 μ
B
4.0 μ
C
3.0 μ
D
1.0 μ
Verified Correct Answer: D.
Step-by-Step Mathematical Solution
Effective capacitance across the parallel = C + C = 2C
Effective capacitance across the circuit = \(\frac{1}{2C} + \frac{1}{2}\) = \(\frac{1 + C}{2C}\)
∴ Effective capacitance across the circuit = \(\frac{1 + C }{2C}\) = \(\frac{1}{1}\)
1 + C = 2C;
2C – C = 1
∴ C = 1.0 μ
Source: WAEC / JAMB / NECO Classroom Archive (Record #76403)