A charge of 1.6 × 10\(^{-10}\) C is placed in a uniform electric field of intensity 2.0 × 10\(^5\) NC\(^{-1}\). What is the magnitude of the electric force exerted on the charge?
A
3.2 × 10\(^{-5}\) N.
B
3.2 × 10\(^5\) N.
C
1.8 × 10\(^{-5}\) N.
D
1.8 × 10\(^5\) N.
Verified Correct Answer: A.
Step-by-Step Mathematical Solution
The force exerted on a charge in an electric field is given by the formula F = qE, where F is the force, q is the charge, and E is the electric field intensity.
Given: the charge q is 1.6 × 10\(^{-10}\) C, and the electric field intensity E is 2.0 × 10\(^5\) NC\(^{-1}\).
Substituting these values into the formula gives F = (1.6 × 10\(^{-10}\) C) × (2.0 × 10\(^5\) NC\(^{-1}\)) = 3.2 × 10\(^{-5}\) N.
Source: WAEC / JAMB / NECO Classroom Archive (Record #76387)