The terminals of a battery of emf 24.0 V and internal resistance of 1.0 Ω is connected to an external resistor 5.0 Ω. Find the terminal p.d.
A
18.0V
B
12.0V
C
16.0V
D
20.0V
Verified Correct Answer: D.
Physical Principles & Numerical Solution
ε = 24.0 V, r=1\Omega, R=5.0\Omega
terminal p·d = ?
ε = IR+Ir = I(R+r)
⇒ IR+Ir = I(R+r)
⇒ I = \(\frac{24}{5+1}\)
⇒ I =\(\frac{24}{6}\)
⇒ I = 4 A
terminal p·d = 4 \times 5
terminal p·d = 20.0 V
Source: WAEC / JAMB / NECO Classroom Archive (Record #67374)