Two bodies each carrying a charge of 2.00 x 10-10C are 5cm apart. Calculate the magnitude of the force between the charges.[\(\frac{1}{4\pi \mathit{E}_o} = 9.00 \times 10^9 Nm^2C{-2}\)]
A
1.44 x 10-7N
B
7.20 x 10-9N
C
7.20 x 10-11N
D
1.44 x 1011N
Verified Correct Answer: A.
Physical Principles & Numerical Solution
f = \(\frac{1}{4 \pi \mathit{E}_o} \times \frac{Q^2}{r^2} = \frac{9 \times 10^9(2 \times 10^{-2})^2}{(0.05)^2}\)
= 1.44 x 10-2N
Source: WAEC / JAMB / NECO Classroom Archive (Record #35082)