A balloon containing 546 cm\(^3\) of air is heated from 0°C to 10°C. If the pressure is kept constant, what will be its volume at 10°C?
A
556 cm\(^3\)
B
526 cm\(^3\)
C
546 cm\(^3\)
D
566 cm\(^3\)
Verified Correct Answer: D.
Physical Principles & Numerical Solution
Using Charles' law;
\(\frac{V_1}{T_1} = \frac{V_2}{T_2}\)
\(\frac{546}{(0 + 273)} = \frac{V_2}{(10 + 273)}\)
V\(_2\) = \(\frac{546 \times 283}{273}\) = 566 cm\(^3\)
Source: WAEC / JAMB / NECO Classroom Archive (Record #76388)