The pressure exerted by the water at the bottom of the reservoir is given by: \(P = \frac{F}{A}\) Given: \( F = 5000 \, \text{N} \) (weight of water), \( L = 10 \, \text{m} \) (length), \( B = 5 \, \text{m} \) (breadth) Calculate the area \( A \): \(A = L \times B = 10 \, \text{m} \times 5 \, \text{m} = 50 \, \text{m}^2\) Calculate the pressure \( P \): \(P = \frac{F}{A} = \frac{5000 \, \text{N}}{50 \, \text{m}^2} = 100 \, \text{Pa}\)