A mass of gas at 40mmHg is heated from 298k to 348k at constant volume. Cal the pressure exerted by the gas.
A
50.21mmHg
B
46.71mmHg
C
42.35mmHg
D
35.12mmHg
Verified Correct Answer: B.
Physical Principles & Numerical Solution
From pressure law
\(\frac{P_1}{T_1} = \frac{P_2}{T_2}\)
P\(_2\) = \(\frac{P_1 \times T_2}{T_1}\)
P\(_1\) = 40mmHg, P\(_2\) = ?
T\(_1\) = 298k, T\(_2\) = 348k
\(\frac{40}{298} = \frac{P_2}{348}\)
P\(_2\) = \(\frac{40\times348}{298}\) = 46.71mmHg
Source: WAEC / JAMB / NECO Classroom Archive (Record #70409)