A reservoir is filled with liquid of density 2000 kgm\(^{-1}\). Calculate the depth at which the pressure in the liquid will be equal to 9100 Nm\(^{-2}\) (g = 10 ms\(^{-2}\))
A
0.262 m
B
0.664 m
C
0.819 m
D
0.455 m
Verified Correct Answer: D.
Physical Principles & Numerical Solution
pressure = p, depth/height = h, density = d, gravity = g
p = hdg
\(\frac{p}{dg} = h\)
\(\frac{9100}{10 * 2000} = h\)
0.455m
Source: WAEC / JAMB / NECO Classroom Archive (Record #64943)