In a hydraulic press, the pump piston exerts a pressure of 100 pa on the liquid. what force is exerted in the second piston of cross sectional area 3 m2?
A
300 N
B
200 N
C
150 N
D
100 N
Verified Correct Answer: A.
Physical Principles & Numerical Solution
Thrust = pressure x area = 100 pa x 3 m2 = 300 N
Source: WAEC / JAMB / NECO Classroom Archive (Record #14296)