The change in volume when 450kg of ice is completely melted is [density of ice = 900 kgm\(^{-3}\), density of water = 1000 kgm\(^{-3}\)]
A
0.50m3
B
0.45m3
C
0.05m3
D
4.50m3
Verified Correct Answer: C.
Physical Principles & Numerical Solution
Vol. of ice = \(\frac{\text{M}}{\text{D}}\) = \(\frac{450}{900}\) = 0.500m\(^3\)
vol. of water = \(\frac{\text{M}}{\text{D}}\) = \(\frac{450}{1000}\) = 0.450m\(^3\)
∴ Difference in vol. = 0.500 - 0.450
= 0.05m\(^3\)
Source: WAEC / JAMB / NECO Classroom Archive (Record #12936)