A projectile is fired at an angle of 30° to the horizontal with a velocity of 40 m/s Calculate the velocity attained after 1 s. [g = 10 m/s\(^2\)]
Verified Correct Answer: .
Physical Principles & Numerical Solution
Calculation of velocity: V = \sqrt[V\(^2\)x + V\(^2\)\(_y\)]
V\(_x\) = 40 Cos30 = 34.6 m/s
V\(_y\) = 40 sin30 - 10(1) = 10 m/s
V = \sqrt[34.6\(^2\) + 10\(^2\)]
V = 36.02m/s
Source: WAEC / JAMB / NECO Classroom Archive (Record #62320)