The diagram shows a uniform meter rule AB which balances horizontally at the 90cm mark when a mass of 0.2kg is suspended from B. Calculate the mass of the meter rule.
Attached Figure / Diagram
A
0.05kg
B
0.20kg
C
0.80kg
D
1.00kg
Verified Correct Answer: A.
Physical Principles & Numerical Solution
M\(_r\)(90 - 50) = 0.2(100 - 90)
40M\(_r\) = 0.2 \times 10
M\(_r\) = \(\frac{2}{40}\) = 0.05kg
Source: WAEC / JAMB / NECO Classroom Archive (Record #55821)