Two points on a velocity-time graph have coordinates (2s, 5m/s) and (4s, 15m/s). Calculate the mean acceleration
A
5.0ms\(^2\)
B
0.83ms\(^2\)
C
1.5ms\(^2\)
D
2.0ms\(^2\)
Verified Correct Answer: A.
Physical Principles & Numerical Solution
Mean acceleration = \(\frac{\Delta V}{\Delta t}\)
Point 1: (2s, 5m/s)
Point 2: (4s,15m/s)
Mean acceleration = \(\frac{ 15 - 5 }{4 - 2}\) = 5.0ms\(^2\)
Source: WAEC / JAMB / NECO Classroom Archive (Record #70683)