A lorry accelerates uniformly in a straight line with acceleration of \(4ms^-2\) and covers a distance of 250 m in a time interval of 10 s. How far will it travel in the next 10 s?
A
650
B
900
C
800
D
250
Verified Correct Answer: A.
Physical Principles & Numerical Solution
We first find the lorry's initial velocity
a = \(4ms^-2\), s= 250m, t= 10, u=?
⇒ ut + \(\frac{1}{2}\times4\times(10^2)
⇒250= 10u + 200
⇒ 250-200 = 10u
⇒ 50 = 10u
⇒U =\frac{50}{10}\) = \(5ms^-1\)
For the next 10s, we set t=20s
= s = (5 \times 20) + \(\frac{1}{2}\times4\times{20^2}\)
= s = 100 + 800
⇒ 900 m
;Distance covered:900-250 =650m
Source: WAEC / JAMB / NECO Classroom Archive (Record #67375)