Two bodies have masses in the ratio3:1. They experience forces which impart to them, acceleration in the ratio 2:9 respectively. Find the ratio of forces the masses experienced
A
1:4
B
2:1
C
2:3
D
2:5
Verified Correct Answer: C.
Physical Principles & Numerical Solution
Given \(\frac{m_{1}}{m_{2}} = \frac{3}{1}\) \(\Rightarrow\) \(m_1\) = 3\(m_2\)
\(\frac{a_{1}}{a_{2}} = \frac{2}{9}\) = \(a_1\) = \(\frac{2a_{2}}{9}\)
\(\frac{F_{1}}{F_{2}}\) = ?
Since F = ma
\(\Rightarrow\) \(\frac{F_{1}}{F_{2}} = \frac{m_{1}a_{1}}{m_{2}a_{2}}\) = \(\frac{(3 \not m_{2})(2 \not a_{2})}{\not m_{2} a_{2} \not a_{3}}\)
\(\frac{F_{1}}{F_{2}} = \frac{2}{3}\) \(\Rightarrow\) 2:3
Source: WAEC / JAMB / NECO Classroom Archive (Record #60751)