A machine of velocity ratio 6 requires an effort of 400 N to raise a load of 800 N through I m. Find the efficiency of the machine
A
55. 6 %
B
50.0%
C
33.3%
D
22.2%
Verified Correct Answer: C.
Physical Principles & Numerical Solution
Efficiency = (MA)/V.R x 100% = (load)/Effort x (1)/V.R
= (800)/400 x (1)/6 x 100% = 33.3%
Source: WAEC / JAMB / NECO Classroom Archive (Record #14293)