Using the diagram above, the effective force pushing it forward at an angle 60º is
Attached Figure / Diagram
A
25.00N
B
28.87N
C
38.50N
D
43.30N
Verified Correct Answer: A.
Step-by-Step Mathematical Solution
The effective force pushing it forward is the horizontal component of the force = F\(_x\) = F Cos\(\theta\)
F\(_x\) = F Cos\(\theta\) = 50 x Cos 60º = 50 x 0.5 = 25N
Source: WAEC / JAMB / NECO Classroom Archive (Record #70481)