A gas with initial volume of 2 X 10\(^{-6}m^3\) is allowed to expand to six times its initial value at constant pressure of 2 x 10\(^5Nm^{-2}\). The work done is?
A
2.0J
B
4. 0 J
C
12.0 J
D
2.4 J
Verified Correct Answer: A.
Physical Principles & Numerical Solution
W = P\DeltaV = 2 x 10\(^5\) * (12 x 10\(^{-6}\) - 2 x 10\(^{-6}\))
= 2 x 10\(^5\) 10 x 10\(^{-6}\)
= 2.0J
Source: WAEC / JAMB / NECO Classroom Archive (Record #7255)