The moon's acceleration due to gravity is \(\frac{1}{6}\) of the earth's value. The weight of a bowling ball on the moon would be
A
6 times its weight on the earth
B
\(\frac{1}{6}\) of its weight on the earth
C
36 times its weight on the earth
D
equal to its weight on the earth
Verified Correct Answer: B.
Step-by-Step Mathematical Solution
W\(_{moon}\) = mass x g = mass x \(\frac{10}{6}\) = \(\frac{10m}{6}\)N
W\(_{earth}\) = mass x g = mass x 10 = 10m
mass = constant
g on earth = 10m/s\(^2\) and g on moon = \(\frac{1}{6}\) x that on earth
Therefore, The weight of a bowling ball on the moon would be \(\frac{1}{6}\), the weight on earth.
Source: WAEC / JAMB / NECO Classroom Archive (Record #70372)