The percentage ratio of holes to conduction electrons in a pure semiconductor is
A
60% 40%
B
30% 70%
C
50% 50%
D
40% 60%
Verified Correct Answer: C.
Physical Principles & Numerical Solution
In a pure (intrinsic) semiconductor, the number of holes is exactly equal to the number of free (conduction) electrons.
Therefore, the percentage ratio is 50% holes to 50% electrons.
Source: Myschool Past Questions Archive (Record #78280)