What mass of silver is deposited by electrolysis when a constant current of 0.8 A is applied for 25 minutes [ z = 12 \times 10\(^{−7}\) kg C\(^{−1}\)]?
A
0.14
B
0.86
C
4.3
D
0.22
Verified Correct Answer: A.
Physical Principles & Numerical Solution
Mass of silver deposited: I =0.8 A , t = 25 min t = 25, z = 12 \times 10\(^{−7}\) kg C\(^{−1}\)
t = 25 \times 60 =1500s
m = z I t = (12 \times 10\(^{−7}\)) \times 0.8 \times 1500 = 1.44 \times 10\(^{−3}\) kg
Source: Myschool Past Questions Archive (Record #78266)