A wheelbarrow inclined at 60º to the horizontal is pushed with a force of 150N. What is the horizontal component of the applied force
A
130N
B
75N
C
60N
D
50N
Verified Correct Answer: B.
Step-by-Step Mathematical Solution
The horizontal component F\(_x\) can be calculated using the formula: F\(_x\) = F⋅ cos (\(\theta\))
F = 150N and \(\theta\) = 60º
F\(_x\) = 150 x 0.5 = 75N (cos 60º = 0.5)
Source: WAEC / JAMB / NECO Classroom Archive (Record #70368)