If the specific gravity of a liquid is 0.76, calculate its density((\(\rho_w\) = 1000Kgm\(^{-3}\))
A
760Kgm\(^{-3}\)
B
76Kgm\(^{-3}\)
C
7.6Kgm\(^{-3}\)
D
7600Kgm\(^{-3}\)
Verified Correct Answer: A.
Physical Principles & Numerical Solution
Specific gravity (SG) is the ratio of the density of the liquid (\(\rho_l\)) to the density of water (\(\rho_w\)):
\( \mathrm{SG} = \frac{\rho_l}{\rho_w} \)
Rearranging for density:
\((\rho_l = \mathrm{SG} \times \rho_w = 0.76 \times 1000 = 760 \, \mathrm{kg \, m^{-3}}\)
Source: Myschool Past Questions Archive (Record #74478)