Using the diagram above, calculate the relative density of x, if the density of methanol is 800kgm\(^{-3}\)
Attached Figure / Diagram
A
0.8
B
0.5
C
1.5
D
2.5
Verified Correct Answer: B.
Physical Principles & Numerical Solution
At equilibrium, the pressures at the bottom of both columns are equal:
ρ\(_m\) \times h\(_m\) \times g = ρ\(_x\) \times h\(_x\) \times g
g cancels out, so:
ρ\(_m\) \times h\(_m\) = ρ\(_x\) \times h\(_x\)
\(\rho_x = \rho_m \times \frac{h_m}{h_x} = 800 \times \frac{7.1}{14.2}\)
\(\frac{7.1}{14.2} = 0.5\)
\(\rho_x = 800 \times 0.5 = 400 \, \text{kg/m³}\)
Relative density of X (with respect to methanol) =
\(\frac{\rho_x}{\rho_m} = \frac{400}{800} = \mathbf{0.5}\)
Source: Myschool Past Questions Archive (Record #70665)