Calculate the power of an object which moves through a distance of 500cm in 1s on a frictionless surface by a horizontal force of 50N
A
200W
B
300W
C
350W
D
250W
Verified Correct Answer: D.
Physical Principles & Numerical Solution
Power = \(\frac{w}{t}\)
Given: F = 50N, s = 500cm → 5m and t = 1s
W = f x s = 50 x 5 = 250J
Power = \(\frac{250}{1}\) = 250W
Source: Myschool Past Questions Archive (Record #70512)