How much heat is required to convert 20 g of ice at 0°C to water at the same temperature? [Specific latent heat of ice = 336 Jg\(^{-1}\)]
A
1.35 × 10\(^3\) J
B
6.72 × 10\(^3\) J
C
5.38 × 10\(^3\) J
D
7.06 × 10\(^3\) J
Verified Correct Answer: B.
Physical Principles & Numerical Solution
The heat required to convert ice at 0^\circC to water at the same temperature is given by the formula: Q = m \times L,
where m is the mass of the ice, and L is the specific latent heat of ice.
Substituting the given values, we get Q = 20 g \times 336 Jg\(^{-1}\) = 6.72 \times 10\(^3\) J.
Source: WAEC / JAMB / NECO Classroom Archive (Record #76361)