Two objects, A and B, accelerate from rest at uniform rates. B accelerates twice as much as Compared to A, B travels
A
at the same distance as A.
B
six times as far.
C
two times as far.
D
three times as far.
Verified Correct Answer: C.
Physical Principles & Numerical Solution
Acceleration of A = a
Acceleration of B = 2a (given)
then: \( S_A = 0 \times t + \frac{1}{2}at^2 = \frac{1}{2}at^2\)
\( S_B = 0 \times t + \frac{1}{2} \times2at^2 = at^2\)
\(t^2 = t^2 ⇒ \frac{2S_A}{a} = \frac{S_B}{a}\)
⇒ \(2S_A = S_B\) ( as a cancels out)
Source: Myschool Past Questions Archive (Record #69423)