A cell of emf 2 V has an internal resistance of 0.5 \Omega. A current of 0.4 A passes through an external resistor, P. Determine the resistance of P.
A
4.5Ω
B
5Ω
C
1Ω
D
4Ω
Verified Correct Answer: A.
Physical Principles & Numerical Solution
E = 2V, r = 0.5\Omega, I = 0.4A, P = ?
E = I( R + r )
R = \(\frac{ E}{I} - r \)
R = \(\frac{ 2}{0.4} - 0.5\)
R = 5 - 0.5 = 4.5\Omega
Source: Myschool Past Questions Archive (Record #69406)