A water fall is 420m high. Calculate the difference in temperature of the water between the top and bottom of the water fall. Neglect heat loses(g = 10.0m-2 specific heat capacity of water = 4.20 x 10\(^3\) JKg-1 K-1)
A
0.1oC
B
1.0oC
C
42oC
D
100oC
E
4.20oC
Verified Correct Answer: B.
Physical Principles & Numerical Solution
Potential Energy = Heat Energy
mgh = Mc\(\Delta \theta = \frac{gh}{c} = \frac{10 \times 240}{4.20 \times 10^3}\)
= 1.0oC
Source: WAEC / JAMB / NECO Classroom Archive (Record #33286)