You are provided with a retort stand, boss head, clamp, stopwatch, slotted weights, hanger, grooved pulley, thread, measuring tape, and other necessary materials.
i. Measure and record the radius R of the pulley.
ii. Setup the apparatus as illustrated in the diagram above, such that the clamp is 1.5 m above the floor.
iii. Tie one end of the thread to the pulley.
iv. Tie the other end of the thread to the hanger.
v. Slot a mass m= 50 g on the hanger.
vi. Wind the thread around the groove of the pulley until the base of the hanger is at a height h = 1.4 m above the floor. Maintain this height h for every other value of m through out the experiment.
vii. Release the mass to unwind the thread.
viii. Determine and record the time t taken by the mass m to reach the floor.
ix. Evaluate t\(^{2}\)
x. Also evaluate
a =\(\frac{2h}{t^{2}}\),T = \(\frac{m}{1000}\) (10 - a) and \(\propto\) = \(\frac{a}{R}\)
xi. Repeat the procedure for four other values of m = 70 g, 90 g, 110 g and 130 g
xii. Tabulate your readings.
xiii. Plot a graph with \(\propto\) on the vertical axis and T on the horizontal axis.
xiv. Determine the slope s, of the graph.
xv. Evaluate I = \(\frac{R}{s}\).
xvi. State two precautions taken to obtain accurate results.
(b)i. Define centripetal force
ii. An object drops to the ground from a height of 2.0 m. Calculate the speed with which it strikes the ground. [g=10 ms\(^{-2}\)]
Verified Correct Answer: .
Physical Principles & Numerical Solution
S/N
m/g
\(t_1\)/s
\(t_2\)/s
\(t_1\)+\(t_2\)/s
t\(^{2}\)/5\(^{2}\)
a=\(\frac{24}{t^{2}}\)
T=\(\frac{m}{1000}\)(10-a)
X=\(\frac{a}{R}\)
1.0
50.0
5.00
5.00
\(\frac{5.0+5.0}{2}\)=5
25.000
0.110
0.490
1.380
2.0
70.0
4.80
4.80
\(\frac{4.8+4.8}{2}\)=4.8
23.040
0.120
0.690
1.50
3.0
90.0
4.60
4.60
\(\frac{4.6+4.6}{2}\)=4.6
21.160
0.130
0.890
1.630
4.0
110.0
4.40
4.40
\(\frac{4.4+4.4}{2}\)=4.4
19.360
0.140
1.080
1.750
5.0
130.0
4.20
4.20
\(\frac{4.2+4.2}{2}\)=4.2
17.640
0.150
1.280
1.880
h = 1.4m = 140cm
R = 0.08m = 8cm
h = 1.4m
R = 8cm = 0.08cm
xvi. Precautions; i
- ensured that no parallax error when talcen my reading with metre rule.
- made sure, the clamp was properly tightened.
- ensured that the experiment was not affected by air interference.
(b)i. Centripetal force (\(F_T\)) is defined as that inward force required to keep an object moving with a constant speed in a circular path \(F_T\) = \(\frac{mo^{2}}{r}\)
ii. K.e = P.e
½ mv\(^{2}\) = mgh
\(\frac{V^{2}}{2}\) = gh
V\(^{2}\) = 2gh
V\(^{2}\) = 2 x 10 x 2
V = \(\sqrt 40\) = 6.37mls.
Source: Myschool Past Questions Archive (Record #59960)