Two fair dice are tossed together once. Find the probability that the sum of the outcomes is at least 10.
A
\(\frac{1}{6}\)
B
\(\frac{1}{12}\)
C
\(\frac{1}{4}\)
D
\(\frac{5}{36}\)
Verified Correct Answer: A.
Step-by-Step Mathematical Solution
Sum ≥ 10 ⇒ 6 favourable outcomes out of 36
Pr(sum at least 10) = \(\frac{6}{36}\) = \(\frac{1}{6}\)
Source: WAEC / JAMB / NECO Classroom Archive (Record #75916)