When two cells of negligible internal resistances and equal e.m.f. denoted by E\(_1\) and E\(_2\) are connected in parallel, combined e.m.f. E is given by
A
E = E\(_1\) + E\(_2\)
B
\(\frac{1}{E} = \frac{1}{E_1} + \frac{1}{E_2}\)
C
E = E\(_1\) = E\(_2\)
D
E = \(\frac{E_1}{E_2}\)
Verified Correct Answer: C.
Physical Principles & Numerical Solution
If two cells of equal emf s are connected in parallel then the effective emf is equal to the emf of any one of the cells.
Source: Myschool Past Questions Archive (Record #59486)