An electron of mass 9.1x 10\(^{-31}\) kg is travelling at a speed of 2.0 x 10\(^6\)ms\(^{-1}\). Calculate the associate wavelength of the electron. [h = 6.6. x 10\(^{-34}\) Js]
A
3.63 x10\(^{-10}\) m
B
3.63 x 10\(^{-8}\) m
C
3.63 x 10\(^{-7}\) m
D
6.89 x 10\(^{-4}\) m
Verified Correct Answer: A.
Physical Principles & Numerical Solution
Using de Broglie wavelength formula: \(\lambda\) = \(\frac{h}{p}\)
P = momentum = mass x velocity = 9.1x 10\(^{-31}\) x 2.0 x 10\(^6\) = 1.82 \times 10\(^{ −24}\) kg m/s
\(\lambda\) = \(\frac{6.6. \times 10^{-34}}{1.82 \times 10^{ −24}}\) = 3.63 x 10\(^{-10}\) m
Source: Myschool Past Questions Archive (Record #59476)